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    [技術(shù)文檔] MathJax公式總結(jié)

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    樓主
    ad*** 發(fā)表于 2021-8-15 17:57:07 | 只看該作者 |倒序?yàn)g覽 |閱讀模式
    MathJax公式總結(jié)基本用法行內(nèi)公式$math$\(math\)$f(x) = 3x + 7$\(f(x) = 3x + 7\) 效果是一樣的  跨行公式\[math\] 或  $$math$$字符
    普通字符在數(shù)學(xué)公式中含義一樣,除了 # $ \% \& \~ _ \^ { };
    若要在數(shù)學(xué)環(huán)境中表示這些符號(hào),需要分別表示為\# \$ \% \& \_ \{ \},即在個(gè)字符前加上\。
    上標(biāo)和下標(biāo)
    用 ^ 來(lái)表示上標(biāo),用 _ 來(lái)表示下標(biāo),看一簡(jiǎn)單例子:
    $$\sum_{i=1}^n a_i=0$$  $$f(x)=x^{x^x}$$
    效果:
    n∑i=1ai=0

    f(x)=xxx

    希臘字母$$\alpha A \beta B \gamma \Gamma \delta \Delta \epsilon E \\\\\varepsilon  \zeta Z \eta H \theta \Theta \vartheta \\\\\iota I \kappa K \lambda \Lambda \mu M \nu N \\\\\xi \Xi o O \pi \Pi \varpi  \rho P \\\\\varrho  \sigma \Sigma \varsigma  \tau T \upsilon \Upsilon \\\\\phi \Phi \varphi  \chi X \psi \Psi \omega \Omega $$
    效果:
    α A β B γ Γ δ Δ ? Eε  ζ Z η H θ Θ ?ι I κ K λ Λ μ M ν Nξ Ξ o O π Π ?  ρ P?  σ Σ ?  τ T υ Υ? Φ φ  χ X ψ Ψ ω Ω

    分?jǐn)?shù)及開(kāi)方$$\frac{1}{4}$$表示開(kāi)平方:$$\sqrt{x^4}$$表示開(kāi) n 次方: $$\sqrt[4]{(a+b)^4}$$
    效果:
    14

    表示開(kāi)平方:√x4

    表示開(kāi) n 次方:4√(a+b)4

    矢量$$\vec{a} \cdot \vec{b}=0$$
    效果:
    →a?→b=0

    累乘$$\prod_{i=0}^n \frac{1}{i^2}$$
    n∏i=01i2

    省略號(hào)(3個(gè)點(diǎn))
    \ldots 表示跟文本底線對(duì)齊的省略號(hào);\cdots表示跟文本中線對(duì)齊的省略號(hào),
    比如:
    $$f(x\_1,x\_x,\ldots,x\_n) = x\_1^2 + x\_2^2 + \cdots + x\_n^2$$
    效果:
    f(x1,xx,…,xn)=x21+x22+?+x2n

    括號(hào)和分隔符
    () 和 [ ] 和 | 對(duì)應(yīng)于自己;
    {} 對(duì)應(yīng)于 { };
    || 對(duì)應(yīng)于 |。
    當(dāng)要顯示大號(hào)的括號(hào)或分隔符時(shí),要對(duì)應(yīng)用 \left 和 \right,如:
    $$\[f(x,y,z) = 3y^2 z \left( 3 + \frac{7x+5}{1 + y^2}\right).\]$$
    效果:
    f(x,y,z)=3y2z(3+7x+51+y2)

    \left. 和 \right. 只用與匹配,本身是不顯示的,比如,要輸出:  
    則用
    dudx|x=0

    多行的數(shù)學(xué)公式$$\begin{eqnarray*}\cos 2\theta & = & \cos^2 \theta - \sin^2 \theta \\\\& = & 2 \cos^2 \theta - 1.\end{eqnarray*}$$
    效果:
    cos2θ=cos2θ?sin2θ=2cos2θ?1.
    其中&是對(duì)其點(diǎn),表示在此對(duì)齊。
    *使latex不自動(dòng)顯示序號(hào),如果想讓latex自動(dòng)標(biāo)上序號(hào),則把*去掉
    矩陣The characteristic polynomial $\chi(\lambda)$ of the $3 \times 3$~matrix  $$ \left( \begin{array}{ccc}  a & b & c \\\\d & e & f \\\\g & h & i \end{array} \right)$$is given by the formula$$\chi(\lambda) = \left| \begin{array}{ccc}  \lambda - a & -b & -c \\\\-d & \lambda - e & -f \\\\-g & -h & \lambda - i \end{array} \right|.$$
    The characteristic polynomial χ(λ) of the 3×3~matrix  
    \left(abcdefghi\right)
    is given by the formula
    \chi(\lambda) = \left|λ?a?b?c?dλ?e?f?g?hλ?i\right|.
    c表示向中對(duì)齊,l表示向左對(duì)齊,r表示向右對(duì)齊。  
    導(dǎo)數(shù)(Derivatives)$\frac{du}{dt} $ and $\frac{d^2 u}{dx^2}$
    效果:dudt and d2udx2
    respectively. The mathematical symbol ? is produced using \partial.
    $$\frac{\partial u}{\partial t}  = h^2 \left( \frac{\partial^2 u}{\partial x^2}  + \frac{\partial^2 u}{\partial y^2}  + \frac{\partial^2 u}{\partial z^2}\right)$$
    效果:
    $$\frac{\partial u}{\partial t}
    = h^2 \left( \frac{\partial^2 u}{\partial x^2}  
    • \frac{\partial^2 u}{\partial y^2}
    • \frac{\partial^2 u}{\partial z^2}\right)$$
    極限(Limits)$$\lim_{x \to +\infty}, \inf_{x > s} , \sup_K$$$$ \lim_{x \to 0} \frac{3x^2 +7x^3}{x^2 +5x^4} = 3.$$
    效果:

    \lim_{x \to +\infty}, \inf_{x > s} , \sup_K

    limx→03x2+7x3x2+5x4=3.

    求和(Sum)$$\sum_{i=1}^{2n}.$$$$\sum_{k=1}^n k^2 = \frac{1}{2} n (n+1).$$
    效果:
    2n∑i=1.

    n∑k=1k2=12n(n+1).

    積分(Integrals)$$\int_a^b f(x)\,dx.$$
    效果:
    ∫baf(x)dx.

    The integral sign is typeset using the control sequence \int, and the
    limits of integration (in this case a and b are treated as a subscript and a superscript on the integral sign.  
    Most integrals occurring in mathematical documents begin with an
    integral sign and contain one or more instances of d followed by another (Latin or Greek) letter, as in dx, dy and dt. To obtain the correct appearance one should put extra space before the d, using \,.
    $$ \int_0^{+\infty} x^n e^{_x} \,dx = n!.$$  $$ \int \cos \theta \,d\theta = \sin \theta.$$  $$ \int_{x^2 + y^2 \leq R^2} f(x,y)\,dx\,dy  = \int_{\theta=0}^{2\pi} \int_{r=0}^R  f(r\cos\theta,r\sin\theta) r\,dr\,d\theta.$$$$ \int_0^R \frac{2x\,dx}{1+x^2} = \log(1+R^2).$$
    效果:
    ∫+∞0xnexdx=n!.
      

    ∫cosθdθ=sinθ.
      

    ∫x2+y2≤R2f(x,y)dxdy=∫2πθ=0∫Rr=0f(rcosθ,rsinθ)rdrdθ.


    ∫R02xdx1+x2=log(1+R2).

    In some multiple integrals (i.e., integrals containing more than one
    integral sign) one finds that LaTeX puts too much space between the
    integral signs. The way to improve the appearance of of the integral is to use the control sequence \! to remove a thin strip of unwanted
    space.
    特殊字符關(guān)系運(yùn)算符
    ±:\pm
    ×:\times
    ÷:\div
    ∣:\mid
    ?:\nmid
    ?:\cdot
    °:\circ
    ?:\ast
    ?:\bigodot
    ?:\bigotimes
    ?:\bigoplus
    ≤:\leq
    ≥:\geq
    ≠:\neq
    ≈:\approx
    ≡:\equiv
    ∑:\sum
    ∏:\prod
    ?:\coprod
    集合運(yùn)算符
    ?:\emptyset
    ∈:\in
    ?:\notin
    ?:\subset
    ?:\supset
    ?:\subseteq
    ?:\supseteq
    ?:\bigcap
    ?:\bigcup
    ?:\bigvee
    ?:\bigwedge
    ?:\biguplus
    ?:\bigsqcup
    對(duì)數(shù)運(yùn)算符
    log:\log
    lg:\lg
    ln:\ln
    三角運(yùn)算符
    ⊥:\bot
    ∠:\angle
    30°:30^°:\circ
    sin:\sin
    cos:\cos
    tan:\tan
    cot:\cot
    sec:\sec
    csc:\csc
    微積分運(yùn)算符
    ′:\prime
    ∫:\int
    ?:\iint
    ?:\iiint
    ?:\iiiint
    ∮:\oint
    lim:\lim
    ∞:\infty
    ?:\nabla
    邏輯運(yùn)算符
    ∵:\because
    ∴:\therefore
    ?:\forall
    ?:\exists
    ≠:\not=
    \not>:\not>
    ?:\not\subset
    戴帽符號(hào)
    ?y:\hat{y}
    ˇy:\check{y}
    ?y:\breve{y}
    連線符號(hào)
    ˉa+b+c+d:\overline{a+b+c+d}
    a+b+c+d_:\underline{a+b+c+d}
    2.0?a+b+c?1.0+d:\overbrace{a+\underbrace{b+c}_{1.0}+d}^{2.0}
    箭頭符號(hào)
    ↑:\uparrow
    ↓:\downarrow
    ?:\Uparrow
    ?:\Downarrow
    →:\rightarrow
    ←:\leftarrow
    ?:\Rightarrow
    ?:\Leftarrow
    ?:\longrightarrow
    ?:\longleftarrow
    ?:\Longrightarrow
    ?:\Longleftarrow

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